Myles Garrett agrees on a new deal to receive the highest annual salary ever for a defensive player.
The Cleveland Browns and their star defensive end Myles Garrett has reached a massive contract agreement that will give Garrett the highest annual salary ever for a defensive player, according to Ian Rapoport NFL Network.
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Garrett will be paid $125 million over the next five years, an annual salary $25 million. $100 million the total will be guaranteed money, with $50 million fully guaranteed immediately.
Over the first three years his career, Garrett has record 30.5 sacks, making him one the highest producing pass-rushers in the league.
In 2019, the Browns finished a disappointing 6-10. After recording 10 sack through the first 10 games the season, Garrett was suspended for the remainder the 2019 season for his involvement in a fight with Steelers quarterback Mason Rudolph.
“They are either mad at you, which is understandable, or they are supportive you—or, both,” he said the Browns season in March. “Those are all understandable reactions to what happened. At the end the day, I’m going to return and do my best to turn things around.”
Garrett is the latest NFL star to lock down a massive deal. Earlier Tuesday, the Chiefs and Chris Jones agreed on a four-year deal to make him one the highest-paid defensive players in the league.